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rem finds the population of 3-B at the end of "year one"
countit = 0
original = 5.49450549*10^16
B3 = 0 rem B3 means 3-B
population = 0
[start]
population = population + original
population = population * 1.01
B3 = B3 + (population/(1.82 * 10^12))
B3 = B3 * 1.01
countit = countit + 1
IF countit = 1000 then [end]
GOTO [start]
[end]
print B3
end
answer: 5.80922992*10e13 or about 5.81*10e13 3-B at end of "year one"
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