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If, a group size is 5.1*10e17 at IS=0,
(group 2-C) the size at IS=1 will be about 1.08 * 10e21
Program #2: (Group "2-C")
countit=0
original=5.1*10^14
rem 5.1*10^14 is added to itself repeatedly
rem which equates to 5.1*10^17
population = 0
[start]
population=population + original
population=population * 1.01
rem During each saturation cycle, superior survivability is figured
rem by multiplying the accumulation by 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end] print population
end
answer: 1.0795545969037893632 * 10e21
(about 1.08 * 10e21 is the total population of 2-C at the end of the first "year")
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