|
rem finding 3-I population at the end of the second year
rem originating from the "first-year" 2-C
countit=1
I3 = 0
population = 1.0795545969037893632*10^21
[start]
I3=I3+(population/(1.96 * 10^14))
I3=I3*1.02
population= population * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
I3=I3+(population/(1.96 * 10^14))
I3=I3*1.02
print I3
end
answer: 2.23736901*10e17
add this to 5.44635665*10e12 (see table 74)
gives the sum: 2.2374234735665*10e17
or about 2.24*10e17 3-I produced in "year two"
|
