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rem finding 3-H population at the end of the second year
rem originating from the "first-year" 2-C
countit=1
H3 = 0
population = 1.0795545969037893632*10^21
[start]
H3=H3+(population/(1.82 * 10^12))
H3=H3*1.01
population= population * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
H3=H3+(population/(1.82 * 10^12))
H3=H3*1.01
print H3
end
answer: 1.24321719*10e16
add this to 5.39428494*10e11 (see table 74)
gives the sum: 1.2432711328494*10e16
or about 1.24*10e16 3-H produced in "year two"
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