A-39

Appendix

A Preliminary Investigation into
An Evolutionary Boundary

rem   finding 3-G population at the end of the second year
rem   originating from the "first-year" 2-C
countit=1
G3 = 0
population = 1.0795545969037893632*10^21
[start]
G3=G3+(population/(1.82 * 10^12))
G3=G3*1.02
population= population * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
G3=G3+(population/(1.82 * 10^12))
G3=G3*1.02
print G3
end

answer:  2.40947431*10e19
add this to   1.51098901*10e10
gives the sum:  2.40947431151098901*10e19
          or about
2.41*10e19   3-G produced in "year two"

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