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rem finding 3-F population at the end of the second year
rem originating from the "first-year" 2-B
countit=1
F3 = 0
population = 5.49450549*10^19
[start]
F3=F3+(population/(1.96 * 10^14))
F3 = F3 * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
F3=F3+(population/(1.96 * 10^14))
F3 = F3 * 1.01
print F3
end
answer: 5.93399226*10e11
add this to 5.99050083*10e10
gives the sum: 6.533042343*10e11
or about 6.53*10e11 3-F produced in "year two"
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