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rem finding 3-E population at the end of the second year
rem originating from the "first-year" 2-B
countit=1
E3 = 0
population = 5.49450549*10^19
[start]
E3=E3+(population/(1.82 * 10^12))
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
E3=E3+(population/(1.82 * 10^12))
print E3
end
updated answer: 3.01895906*10e10
answer: 3.01895906*10e10
add this to 1.51098901*10e10
gives the sum: 4.52994807*10e10
or about 4.53*10e10 3-E produced in "year two"
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