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rem finding 3-C population at the end of the second year
rem originating from the "first-year" 2-A
countit=1
C3 = 0
population = 1.16306248*10^23
[start]
C3=C3+(population/(1.96 * 10^14))
C3=C3*1.02
population= population * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
C3=C3+(population/(1.96 * 10^14))
C3=C3*1.02
print C3
end
answer: 2.41043848*10e19 or about 2.41*10e19 3-C
add this to 5.86530715*10e14
gives the sum: 2.4104971330715*10e19
or about 2.41*10e19 3-C produced in "year two"
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