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rem finding 3-B population at the end of the second year
rem originating from the "first-year" 2-A
countit=1
B3 = 0
population = 1.16306248*10^23
[start]
B3=B3+(population/(1.82 * 10^12))
B3=B3*1.01
population= population * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
B3=B3+(population/(1.82 * 10^12))
B3=B3*1.01
print B3
end
answer: 1.33938503*10e18 adding this to 5.80922992*10e13
gives: 1.3394431222992*10e18
or about 1.34*10e18 total 3-B produced in "year two"
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