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rem finding 3-A population at the end of the second year
rem originating from the "first-year" 2-A
countit=1
A3 = 0
population = 1.16306248*10^23
[start]
A3=A3+(population/(1.82 * 10^12))
A3=A3*1.02
population= population * 1.01
countit=countit + 1
IF countit=1000 then [end]
GOTO [start]
[end]
A3=A3+(population/(1.82 * 10^12))
A3=A3*1.02
print A3
print population
end
answers:
2.59585683*10e21 or about 2.59*10e21 3-A
2413545300477396001644085248 or about 2.4*10e27 2-A
Adding 2.59585683*10e21 (see above) to
6.31648463*10e16 (see table: 74) results in:
2.5959199948463*10e21
or about 2.59*10e21 total 3-A produced in "year two"
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