A-16

Appendix

A Preliminary Investigation into
An Evolutionary Boundary

Figuring the first "year's" population of 3-I

5.10204082*10e14  2-C will be produced per saturation cycle.
One in 1.96*10e14 is the number of
3-I generated by 2-C organisms

countit = 0
original = 5.10204082*10^14
I3 = 0                   
population =  0
[start]
population = population + original
population = population * 1.01
I3 = I3 + (population/(1.96*10^14))
I3 = I3 * 1.02     
countit = countit + 1                           
IF countit = 1000 then [end]                 
GOTO [start]                                                             
[end]
print I3
end

answer:  5.44635665*10e12  or about  5.45*10e12 
3-I at the end of "year one"

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