Figuring the first "year's" population of 3-D
One in 1.82*10e12 divisions of A-1 organisms will produce a 2-B organism. 5.49450549e16 2-B will be produced per saturation cycle. One in 1.82*10e12 is also the number of 3-D generated by 2-B organisms
rem finds populations of 2-B and 3-D at the end of "year one" countit = 0 original = 5.49450549*10^16 D3 = 0 population = 0 [start] population = population + original D3 = D3 + (population/(1.82*10^12)) D3 = D3 * 1.01 countit = countit + 1 IF countit = 1000 then [end] GOTO [start] [end] print population print D3 end answer: 54945054900000000000 or 2-B at end of "year one" is 5.49450549*10e19 --- 6.45130858*10e12 about 6.5*10e12 3-D at the end of "year one"
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