Figuring the first "year's" population of 3-D
One in 1.82*10e12 divisions of A-1 organisms will produce a 2-B organism.
5.49450549e16 2-B will be produced per saturation cycle.
One in 1.82*10e12 is also the number of 3-D generated by 2-B organisms
rem finds populations of 2-B and 3-D at the end of "year one"
countit = 0
original = 5.49450549*10^16
D3 = 0
population = 0
population = population + original
D3 = D3 + (population/(1.82*10^12))
D3 = D3 * 1.01
countit = countit + 1
IF countit = 1000 then [end]
54945054900000000000 or 2-B at end of "year one" is 5.49450549*10e19 ---
6.45130858*10e12 about 6.5*10e12 3-D at the end of "year one"