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One in 1.82*10e12 divisions of 1-A will produce 2-A in the first "year".
5.49450549*10e16 2-A will be produced per saturation cycle. ("year one")
One in 1.96*10e14 is the number of 3-C generated by 2-A organisms
rem finds population of 3-C at the end of "year one"
countit = 0
original = 5.49450549*10^16
rem 5.49450549*10^16 per saturation cycle (2-A)
C3 = 0
population = 0
[start]
population = population + original
population = population * 1.01
C3 = C3 + (population/(1.96*10^14))
C3 = C3 * 1.02
countit = countit + 1
IF countit = 1000 then [end]
GOTO [start]
[end]
print C3
end
answer: 5.86530715*10e14 or about 5.87*10e14 3-C at end of "year one"
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